Blueprint 4 Workbook Answer Key Page
[ \beginbmatrixx\y\endbmatrix=A^-1\mathbfb= \frac122 \beginbmatrix 4 & 2\ -5 & 3 \endbmatrix \beginbmatrix7\-1\endbmatrix =\frac122\beginbmatrix 4(7)+2(-1)\ -5(7)+3(-1) \endbmatrix =\frac122\beginbmatrix 28-2\ -35-3 \endbmatrix =\frac122\beginbmatrix 26\ -38 \endbmatrix ]
Thus, [ x = \frac2622= \frac1311\approx1.182,\qquad y = \frac-3822= -\frac1911\approx-1.727. ] (x = \dfrac1311;(\approx1.182),\qquad y = -\dfrac1911;(\approx-1.727))
[ A^-1= \frac122\beginbmatrix 4 & 2\ -5 & 3 \endbmatrix ] blueprint 4 workbook answer key
[ t = \frac\barx_A - \barx_BSE = \frac
Directly use the equivalence (1\ \textkW·h=3.6\times10^6\ \textJ); multiply by 5.6. Problem 27
(5.6\ \textkW·h=2.016\times10^7\ \textJ)
(5(13/11) + 4(-19/11) = 65/11 - 76/11 = -11/11 = -1) ✔️ [ x = \frac2622= \frac1311\approx1.182
Strang, Linear Algebra and Its Applications , 5th ed., §1.2 (Cramer’s Rule). Problem 27.5 – Two‑Sample t‑Test (Module 3) Problem Statement A manufacturing process produces two batches of polymer samples. Batch A (n₁ = 12) has mean tensile strength (\barx_A=68.4) MPa and standard deviation (s_A=3.2) MPa. Batch B (n₂ = 15) has (\barx_B=71.1) MPa and (s_B=2.9) MPa.