Fluid Power Practice Problems Answer Key - Pdf

( A_r = A_p - A_rod = 7.07 - \frac\pi \times (1.5)^24 = 7.07 - 1.77 = 5.30 \text in^2 )

( Q_th = \frac\textdisp \times \textrpm231 = \frac2.5 \times 1200231 = \frac3000231 = 12.99 \text GPM ) fluid power practice problems answer key pdf

( F_ret = 1500 \times 5.30 = 7,950 \text lbf ) ( A_r = A_p - A_rod = 7

( F_ext = P \times A_p = 1500 \times 7.07 = 10,605 \text lbf ) 605 \text lbf )