SMC Episodes

Start with (f(x)=x^2). Apply: vertical compression by (1/2), shift right 3, shift up 4. [ y = \frac12 (x-3)^2 + 4 ] 4. Inverse Functions Switch (x) and (y) in (y=f(x)), then solve for (y). Inverse exists if (f) is one‑to‑one (passes horizontal line test).

(f(x)=x^2+1), (g(x)=2x-3) Find ((f\circ g)(x) = f(g(x)) = (2x-3)^2 + 1 = 4x^2 -12x + 10) 3. Transformations of Functions Given (y = a,f(k(x-d)) + c):

(t_n = ar^n-1) Sum of (n) terms: (S_n = \fraca(r^n-1)r-1, r\neq 1)

(y = a\sin(k(x-d)) + c) Amplitude = (|a|), Period = (360^\circ/|k|) (or (2\pi/|k|) rad), Phase shift = (d), Vertical shift = (c)

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Functions Grade 11 Textbook -

Start with (f(x)=x^2). Apply: vertical compression by (1/2), shift right 3, shift up 4. [ y = \frac12 (x-3)^2 + 4 ] 4. Inverse Functions Switch (x) and (y) in (y=f(x)), then solve for (y). Inverse exists if (f) is one‑to‑one (passes horizontal line test).

(f(x)=x^2+1), (g(x)=2x-3) Find ((f\circ g)(x) = f(g(x)) = (2x-3)^2 + 1 = 4x^2 -12x + 10) 3. Transformations of Functions Given (y = a,f(k(x-d)) + c): functions grade 11 textbook

(t_n = ar^n-1) Sum of (n) terms: (S_n = \fraca(r^n-1)r-1, r\neq 1) Start with (f(x)=x^2)

(y = a\sin(k(x-d)) + c) Amplitude = (|a|), Period = (360^\circ/|k|) (or (2\pi/|k|) rad), Phase shift = (d), Vertical shift = (c) shift right 3