: Perform bitwise AND with mask to find network ID; add inverse mask to find broadcast. Part 6 – Supernetting / Route Summarization Question : Summarize these Class C networks into a single route: 192.168.4.0/24, 192.168.5.0/24, 192.168.6.0/24, 192.168.7.0/24
: Large contiguous block from 10.0.22.0/24 onward. Epilogue Alex submits the workbook. The instructor’s note on top says: “Version 2.0 completed correctly. Next step: practice until you can do each problem in under 45 seconds.”
Below is Alex’s with explanations written in the margins. Part 1 – Address Classification & Default Masks | IP Address | Class | Default Subnet Mask | Network ID | Host ID | |-----------------------|-----------|-------------------------|----------------|--------------| | 10.250.1.15 | A | 255.0.0.0 | 10.0.0.0 | 250.1.15 | | 172.31.200.99 | B | 255.255.0.0 | 172.31.0.0 | 200.99 | | 192.168.5.10 | C | 255.255.255.0 | 192.168.5.0 | 10 | | 203.0.113.88 | C | 255.255.255.0 | 203.0.113.0 | 88 | | 8.8.8.8 | A | 255.0.0.0 | 8.0.0.0 | 8.8.8 |
Alex later passes the CCNA – thanks to the methodical practice of subnetting by hand.
JOY TO INSTALL